基于相位编码波形捷变和CFAR技术的抗同频干扰

doi:10.12305/j.issn.1001-506X.2022.04.18

摘要/Abstract

摘要：

同频干扰具有压制干扰和欺骗干扰的特点, 是一种较难对抗的雷达干扰方式, 而灵活的波形设计是抗同频干扰的一种新途径。本文对同频干扰的机理和信号特性进行了分析和总结, 而后研究了两级相位编码信号变波形脉压失配后输出信号的特点。在此基础上提出了利用相位编码变波形联合恒虚警(constant false-alarm rate, CFAR)技术抗同频干扰的方法, 通过合理设置相位编码波形和匹配压缩滤波器, 使同频干扰信号处于脉压失配状态, 再通过CFAR处理滤除干扰信号。仿真结果表明, 合理设置相位编码波形并配合CFAR检测处理, 能够有效地从同频干扰中提取出有用的目标回波信号, 并且对强同频干扰具有较好的适应性。

关键词: 同频干扰, 相位编码, 恒虚警, 波形设计

Abstract:

Co-channel interference has the characteristics of suppressing interference and deceiving interference, which is an interference difficult to resist. Waveform design is a new way to resist co-channel interference. This paper analyzes and summarizes the mechanism and signal characteristics of the same frequency interference, and studies the characteristics of the output signal after the two-stage phase encoding variable waveform pulse compressing mismatch. On this base, a method of using phase encoding variable waveform combined with constant false-alarm rate (CFAR) to resist the co-channel interference is proposed. By setting the phase encoding waveform and matching compression filter reasonably, the interference is in a state of mismatch, and then the interference is filtered through the CFAR. The simulation results show that the two-stage phase encoding has a reasonable setting of waveform and cooperating with CFAR detection processing, which can effectively extract the useful target echo signal from the interference, and is excellent in applicability to strong co-channel interference.

Key words: co-channel interference, phase encode, constant false-alarm rate (CFAR), wave form design

中图分类号:

TN973

夏栋, 张凯旋, 丁友宝, 李宝鹏. 基于相位编码波形捷变和CFAR技术的抗同频干扰[J]. 系统工程与电子技术, 2022, 44(4): 1210-1219.

Dong XIA, Kaixuan ZHANG, Youbao DING, Baopeng LI. Co-channel interference resistance based on agile wave form of phase encode and CFAR technology[J]. Systems Engineering and Electronics, 2022, 44(4): 1210-1219.

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位长	码组序列
2	++(1、1) 或+-(1、-1)
3	++-(1、1、-1)
4	+++-(1、1、1、-1) 或++-+(1、1、-1、1)
5	+++-+(1、1、1、-1、1)
7	+++--+-(1、1、1、-1、-1、1、-1)
11	+++---+--+-(1、1、1、-1、-1、-1、1、-1、-1、1、-1)
13	+++++--++-+-+(1、1、1、1、1、-1、-1、1、1、-1、1、-1、1)

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